ENDEIT

Tenor saxophone solo · 1964

Wayne Shorter: Infant Eyes

Key
E♭ major
Tempo
51 BPM SLOW
Rhythm feel
Ballad
Style
Postbop
Choruses
1
Form
A9B9A9

Wayne Shorter's solo on “Infant Eyes” has 157 notes in 127 seconds (1.2 notes per second), spanning 33 semitones from Ab2 to F5. The average tempo is 51 BPM with a ballad feel. About 62% of the melodic motion is stepwise (one or two semitones).

Notes

157Notes
127sSolo length
1.2Notes per second
Ab2–F5Range (33 semitones)
62%Stepwise motion

Pitch-class distribution

Most frequent intervals

  • +2 ×26
  • -1 ×26
  • +1 ×25
  • -2 ×18
  • -3 ×17
  • 0 ×9

Changes played over

A1
Gm7
Fm7
E♭maj7
A79♭13
G♭maj7
Fsus79
E♭m7
B♭sus79
B♭7
B1
E♭maj7
Emaj7/E♭
E♭maj7911♯
Emaj7911♯
Bmaj7
B♭sus79
A♭m7
E♭sus79
D+79♯
A2
Gm7
Fm7
E♭maj7
A79♭13
G♭maj7
Fsus79
E♭m7
B♭sus79
B♭sus79
I1
Gm7
Fm7

Record

Record
The Blue Note Years - The Best of Wayne Shorter · Blue Note · 1988
Recorded
1964-12-24
Line-up
Freddie Hubbard (tp); Herbie Hancock (p); Ron Carter (b); Elvin Jones (dr); Wayne Shorter (ts)
Composer
Shorter
Solo length
02:35-04:44

Source: Weimar Jazz Database, Jazzomat Research Project (HfM Weimar), ODbL 1.0.